If sec theta = 1 1/4, then tan theta/2 is equal to 1) 1/3 2) 3/4 3) 1/4 4) 5/4 Answer (1) 1/3 Solution Given, sec θ = 1 1/4 = 5/4Question This question is from textbook saxon algebra 2 Show that 1tan^2 (theta)=sec^2(theta) for 765 degrees This question is from textbook saxon algebra 2 Answer by solver() (Show Source) You can put this solution on YOUR website!This article uses Greek letters such as alpha (α), beta (β), gamma (γ), and theta (θ) to represent anglesSeveral different units of angle measure are widely used, including degree, radian, and gradian () 1 full circle () = 360 degree = 2 π radian = 400 gonIf not specifically annotated by (°) for degree or for gradian, all values for angles in this article are assumed to be given in
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Sec6)theta=tan6)theta+3 tan^(2)theta sec^(2)theta+1
Sec6)theta=tan6)theta+3 tan^(2)theta sec^(2)theta+1-Click here👆to get an answer to your question ️ Solve (sec^2 theta 1)(1 cosec^2 theta) = 1Prove that ( sec theta tan theta )^2 = 1 sin theta / 1 sin theta Watch later Share Copy link Info Shopping Tap to unmute If playback doesn't begin shortly, try restarting your device
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Click here👆to get an answer to your question ️ If tan^2 theta = 1 e^2 , then prove that sec theta tan^3 theta cosec theta = (2 e^2)^3/2Prove the following trigonometric identity $$1 \tan^2\theta = \sec^2\theta$$ I'm curious to know of the different ways of proving this depending on different characterizations of tangent and seTo ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Most general value of `theta` satisfying equation `tan^2 theta sec 2theta = 1` is
I'll do you one better To begin, we know and So But ButMay 29, 21 · Which compound angle formula is the easiest to use to develop the expression cos^2 theta sin^2 theta?Jul 16, 18 · The answer is =sec^2theta We need tantheta=sintheta/costheta sin^2thetacos^2theta=1 1/costheta=sectheta The expression is 1tan^2theta=1sin^2theta/cos^2theta =(cos^2thetasin^2theta)/cos^2theta =1/cos^2theta =sec
Answer to Given \sec(\theta) = 3;\ 90^\circ \lt \theta \lt 180^\circ, find the exact value of \sin(2\theta),\ \cos(2\theta),\ \tan(2\theta) ByOct 12, 16 · see below sec^2theta(1cos^2theta)=tan^2theta Left Side =sec^2theta(1cos^2theta) =sec^2thetasin^2theta =1/cos^2theta * sin^2 theta =sin^2theta/cos^2theta =tanOn adding the two fractions, we have ^@ \begin{align} & \cot^2 \theta \left( \dfrac{ \sec \theta 1 } { 1 \sin \theta } \right) \sec^2 \theta \left( \dfrac
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One can show using simple geometry that t = tan(φ/2) The equation for the drawn line is y = (1 x)t The equation for the intersection of the line and circle is then a quadratic equation involving t The two solutions to this equation are (−1, 0) and (cosAnswer to cot^2(theta)(1tan^2)(theta) I came up with (cot^2(theta)(sec^2)(theta) cos^2(theta)/sin^2(theta) * (1/cosProve the trig problem by making the left side equal to the right secant theta 1 * secant theta 1
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$\begingroup$ Use $\sec^2\theta = \tan^2\theta 1$ Then you have a quadratic in $\sec\theta$ $\endgroup$ – Simon S Aug 5 '15 at 1958 $\begingroup$ I did that but I didn't notice it was a quadratic, thank you!`=sec theta xx cosec theta` RHS = `tan theta cot theta = (sin theta)/(cos theta) cos theta/sin theta = (sin^2 theta cos^2 theta)/(cos theta sin theta) = 1/cos theta xx 1/sin theta = sec theta xx cosec theta`Sin ^2 (x) cos ^2 (x) = 1 tan ^2 (x) 1 = sec ^2 (x) cot ^2 (x) 1 = csc ^2 (x) sin(x y) = sin x cos y cos x sin y cos(x y) = cos x cosy sin x sin y
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Q If $\int \frac{d\theta}{cos^{2}\,\theta\left(tan\,2\thetasec\,2\theta\right)}=$ $\lambda\,tan\theta2\,log_{e}\leftf \left(\theta\right)C\right$ where C is aDec , 19 · A solution of the equation (1 tan theta) (1 tan theta) sec^2 theta 2^tan^2theta = 0 where theta lies in the interval ( pi/2, pi/2) is given by 11thMay 19, 19 · Given Sec theta= 5/4 hypotenuse = 5 adjacent side = 4 Then by Pythagoras theoremoppsite side = root ((5)^2 (4)^2) = root (25 16) = root 9 opposite side = 3 tan theta = 3/4 sin theta = 3/5 3/4 ÷ 1 9/16 3/4 ÷ 25/16 = 12/25 = LHS 3/5 ÷ 5/4 = 12/25 = RHS LHS = RHS Hence Proved Hope it helps Please mark it as the brainliest Cheers Hermione
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Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutorProve the following identities (1 cot θ – cosec θ)(1 tan θ sec θ) = 2 Maharashtra State Board HSC Arts 11th Textbook Solutions 7817 Important Solutions 3 Question Bank Solutions 5236 Concept Notes & Videos 332 (sin theta cos theta 1)/sin theta)((cos theta sin theta 1)/cos theta`a^2/b^2 1 = c^2/b^2` By definition `a/b = tan theta` and `b/c = cos theta` (which means `c/b = 1/(cos theta)` so `tan^2 theta 1 = 1/(cos^2 theta)` which gives `tan^2 theta 1 = sec^2 theta`
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$\tan^2{\theta} \,=\, \sec^2{\theta}1$ The square of tan function equals to the subtraction of one from the square of secant function is called the tan squared formula It is also called as the square of tan function identity Introduction The tangent functions are often involved in trigonometric expressions and equations in square form TheThe value of (sec A tan A) (1 − sin A) is equal to View solution The positive values of a for which the equation x a = sin 2 π x will have no solution isLHS = `(sec^2 theta 1)(cosec^2 theta1)` =`tan^2 theta xx cot^2 theta ( ∵ sec^2 theta tan^2 theta = 1 and cosec^2 theta cot^2 theta =1)`
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Answer to Verify the identity sec (theta)/1tan^2 (theta) = cos (theta) By signing up, you'll get thousands of stepbystep solutions to yourDec 15, · If tan θ = 1/√7, then (cosec 2 θ – sec 2 θ)/ (cosec 2 θ sec 2 θ) is equal to (1) 1/2 (2) 3/4 (3) 5/4 (4) 2 Answer (2) ¾ Solution Given, tan θ =1/√7$\endgroup$ – TheNewGuy Aug 5 '15 at 1959
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Tan theta = 1/2Jun 29, · Using the identity $1\text{tan}^2(\theta)=\text{sec}^2(\theta) \Rightarrow \text{tan}^2(\theta)=\text{sec}^2(\theta) 1$ $$\sec^2(\theta) \tan^2(\theta) = 1$$ $$\sec^2(\theta) \sec^2(\theta)1 = 1$$ $$2\sec^2(\theta)=2 $$ $$\sec(\theta)=\pm 1 $$ Once the interval given is $0, 2\pi)$, the solution is $\theta=\{0, \pi\}$Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutor
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Hint (This expands the hint of @Bernard it was what I needed to make it work) Note that $\frac{1}{1\tan^{2}(\theta)}=\frac{1\tan^{2}(\theta)}{(1\tan^{2Sep 14, 16 · #sec^2 t = 1/(cos^2 t)# #1 sin^2 t = cos^2 t# We get #1/(cos^2 t) (sin^2 t)/(cos^2 t) = (1 sin^2 t)/cos^2 t = cos^2 t/(cos^2 t) = 1# Answer link Related questions What does it mean to prove a trigonometric identity?If 1 Minus Tan Square Theta Sec Square Theta 1 2 Then If (1 tan 2 θ)/sec 2 θ = 1/2, then the general value of θ is 1) nπ ± π/6 2) nπ π/6 3) 2nπ ± π/6 4) None of these Answer (1) nπ ± π/6 Solution Given, (1 – tan 2 θ)/sec 2 θ = 1/2 Using the identity sec 2 A – tan 2 A = 1, (1
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Mar 04, 18 · Click here 👆 to get an answer to your question ️ Sec^6 theta = tan^6 theta3tan square theta sec square theta 1 aarzookhatri23 aarzookhatri23 Math Secondary School answered Sec^6 theta = tan^6 theta3tan square theta sec square theta 1 2 See answersLHS = `(tan^2 theta)/(sec theta 1)^2 ` `= (sec^2 theta 1)/(sec theta 1)^2` `= ((sec theta 1)(sec theta 1))/(sec theta 1)^2` `= (sec theta 1)/(sec theta 1)` `= (1/cos theta 1)/(1/cos theta 1)` `= ((1 cos theta)/cos theta)/((1 cos theta)/cos theta)` `= (1 cos theta)/(1Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more
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Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreHow do you prove #(1\cos^2 x)(1\cot^2 x) = 1#?Addition formula for sine subtraction formula for sine addition formula for cosine subtraction formula for cosine The graph of y = tan x has
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Sep , 18 · In this video, we will prove the identity square of tangent of theta 1 = square of secant of thetaOther topics for the videoProof of the identity 1 tanJul 21, 16 · Click here 👆 to get an answer to your question ️ PT sec 8 theta1/sec 4 theta1=tan 8 theta/tan 2 theta sab3irsaikahke sab3irsaikahke Math Secondary School answered • expert verified PT sec 8 theta1/sec 4 theta1=tan 8 theta/tan 2 theta 2 See answersProve the Following Tan 3 θ − 1 Tan θ − 1 = Sec 2 θ Tan θ
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2 tan1 (cos x) = tan1 (cosec2 x), then x = 25 People For Programme A 50 People For Programme B 10 People For Both So The Number Of Employees Employed Only A Is 3 By 4 Plus 5 By 36 Plus 7 By 144 Plus 9 By 400 Infinite Terms EqualLet theta = x tan x=1/2 = prep(AB)/base(BC) Let in right angled triangle B=90° ,prep(AB) =k unit then base (BC)= 2k units AC^2=AB^2BC^2 AC^2= k^2 4k^2=5k^2 AC (hypotenuse) =k√5units sin x= prep(AB)/hypo(AC) sin x=k units/k√5units sinHow do you prove #\csc \theta \times \tan \theta = \sec \theta#?
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